Base | Representation |
---|---|
bin | 11101111000011101010101… |
… | …000100000100101000111001 |
3 | 122020022221001222212000212220 |
4 | 131320131111010010220321 |
5 | 114211214033120434431 |
6 | 1143302541511154253 |
7 | 36453002466201432 |
oct | 3570352504045071 |
9 | 566287058760786 |
10 | 131423131421241 |
11 | 3896a267547680 |
12 | 128a6824975989 |
13 | 58441c054385a |
14 | 2464cb0906489 |
15 | 102d93d327b96 |
hex | 778755104a39 |
131423131421241 has 8 divisors (see below), whose sum is σ = 191160918430944. Its totient is φ = 79650382679520.
The previous prime is 131423131421227. The next prime is 131423131421303. The reversal of 131423131421241 is 142124131324131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 131423131421241 - 25 = 131423131421209 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (33), and also a Moran number because the ratio is a prime number: 3982519133977 = 131423131421241 / (1 + 3 + 1 + 4 + 2 + 3 + 1 + 3 + 1 + 4 + 2 + 1 + 2 + 4 + 1).
It is not an unprimeable number, because it can be changed into a prime (131423131421201) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1991259566956 + ... + 1991259567021.
It is an arithmetic number, because the mean of its divisors is an integer number (23895114803868).
Almost surely, 2131423131421241 is an apocalyptic number.
131423131421241 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
131423131421241 is a deficient number, since it is larger than the sum of its proper divisors (59737787009703).
131423131421241 is a wasteful number, since it uses less digits than its factorization.
131423131421241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3982519133991.
The product of its digits is 13824, while the sum is 33.
Adding to 131423131421241 its reverse (142124131324131), we get a palindrome (273547262745372).
The spelling of 131423131421241 in words is "one hundred thirty-one trillion, four hundred twenty-three billion, one hundred thirty-one million, four hundred twenty-one thousand, two hundred forty-one".
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