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131423343310443 = 343807781103481
BaseRepresentation
bin11101111000011101100001…
…101100010111011001101011
3122020022221121202120010020010
4131320131201230113121223
5114211220001341413233
61143303014520503003
736453010651214262
oct3570354154273153
9566287552503203
10131423343310443
113896a366110118
12128a688391aa63
135844225401592
142464cd0b015d9
15102d951c2eb63
hex778761b1766b

131423343310443 has 4 divisors (see below), whose sum is σ = 175231124413928. Its totient is φ = 87615562206960.

The previous prime is 131423343310429. The next prime is 131423343310451. The reversal of 131423343310443 is 344013343324131.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 131423343310443 - 221 = 131423341213291 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131423343310543) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21903890551738 + ... + 21903890551743.

It is an arithmetic number, because the mean of its divisors is an integer number (43807781103482).

Almost surely, 2131423343310443 is an apocalyptic number.

131423343310443 is a deficient number, since it is larger than the sum of its proper divisors (43807781103485).

131423343310443 is an equidigital number, since it uses as much as digits as its factorization.

131423343310443 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43807781103484.

The product of its (nonzero) digits is 373248, while the sum is 39.

Adding to 131423343310443 its reverse (344013343324131), we get a palindrome (475436686634574).

The spelling of 131423343310443 in words is "one hundred thirty-one trillion, four hundred twenty-three billion, three hundred forty-three million, three hundred ten thousand, four hundred forty-three".

Divisors: 1 3 43807781103481 131423343310443