131423410104113 has 4 divisors (see below), whose sum is σ = 138340431688560. Its totient is φ = 124506388519668.

The previous prime is 131423410104001. The next prime is 131423410104127. The reversal of 131423410104113 is 311401014324131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131423410104113 - 2³² = 131419115136817 is a prime.

It is a super-2 number, since 2×131423410104113² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131423410104143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3458510792195 + ... + 3458510792232.

It is an arithmetic number, because the mean of its divisors is an integer number (34585107922140).

Almost surely, 2^{131423410104113} is an apocalyptic number.

It is an amenable number.

131423410104113 is a deficient number, since it is larger than the sum of its proper divisors (6917021584447).

131423410104113 is an equidigital number, since it uses as much as digits as its factorization.

131423410104113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6917021584446.

The product of its (nonzero) digits is 3456, while the sum is 29.

Adding to 131423410104113 its reverse (311401014324131), we get a palindrome (442824424428244).

The spelling of 131423410104113 in words is "one hundred thirty-one trillion, four hundred twenty-three billion, four hundred ten million, one hundred four thousand, one hundred thirteen".