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131423511305121 = 376258262443101
BaseRepresentation
bin11101111000011101101011…
…101101001101101110100001
3122020022222001110200010121020
4131320131223231031232201
5114211220322343230441
61143303043321320053
736453015061151550
oct3570355355155641
9566288043603536
10131423511305121
113896a441a22aa2
12128a6910036029
135844251160c09
142464d09151d97
15102d961865e66
hex77876bb4dba1

131423511305121 has 8 divisors (see below), whose sum is σ = 200264398179264. Its totient is φ = 75099149317200.

The previous prime is 131423511305089. The next prime is 131423511305123. The reversal of 131423511305121 is 121503115324131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 131423511305121 - 25 = 131423511305089 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (131423511305123) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3129131221530 + ... + 3129131221571.

It is an arithmetic number, because the mean of its divisors is an integer number (25033049772408).

Almost surely, 2131423511305121 is an apocalyptic number.

It is an amenable number.

131423511305121 is a deficient number, since it is larger than the sum of its proper divisors (68840886874143).

131423511305121 is an equidigital number, since it uses as much as digits as its factorization.

131423511305121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6258262443111.

The product of its (nonzero) digits is 10800, while the sum is 33.

Adding to 131423511305121 its reverse (121503115324131), we get a palindrome (252926626629252).

The spelling of 131423511305121 in words is "one hundred thirty-one trillion, four hundred twenty-three billion, five hundred eleven million, three hundred five thousand, one hundred twenty-one".

Divisors: 1 3 7 21 6258262443101 18774787329303 43807837101707 131423511305121