131424133213001 has 4 divisors (see below), whose sum is σ = 131434524949632. Its totient is φ = 131413741476372.

The previous prime is 131424133212961. The next prime is 131424133213019. The reversal of 131424133213001 is 100312331424131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131424133213001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131424133213501) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5195849345 + ... + 5195874638.

It is an arithmetic number, because the mean of its divisors is an integer number (32858631237408).

Almost surely, 2^{131424133213001} is an apocalyptic number.

It is an amenable number.

131424133213001 is a deficient number, since it is larger than the sum of its proper divisors (10391736631).

131424133213001 is a wasteful number, since it uses less digits than its factorization.

131424133213001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10391736630.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 131424133213001 its reverse (100312331424131), we get a palindrome (231736464637132).

The spelling of 131424133213001 in words is "one hundred thirty-one trillion, four hundred twenty-four billion, one hundred thirty-three million, two hundred thirteen thousand, one".