Base | Representation |
---|---|
bin | 11101111000011110010100… |
… | …110100101001100100001011 |
3 | 122020100000211112200100201212 |
4 | 131320132110310221210023 |
5 | 114211223230441320021 |
6 | 1143303240002403335 |
7 | 36453041135402642 |
oct | 3570362464514413 |
9 | 566300745610655 |
10 | 131424201120011 |
11 | 3896a766346148 |
12 | 128a6a8306054b |
13 | 58443310453c7 |
14 | 2464d729d8359 |
15 | 102d9a21c585b |
hex | 778794d2990b |
131424201120011 has 4 divisors (see below), whose sum is σ = 131447979703632. Its totient is φ = 131400422536392.
The previous prime is 131424201120007. The next prime is 131424201120067. The reversal of 131424201120011 is 110021102424131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131424201120011 - 22 = 131424201120007 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131424201120811) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11889283520 + ... + 11889294573.
It is an arithmetic number, because the mean of its divisors is an integer number (32861994925908).
Almost surely, 2131424201120011 is an apocalyptic number.
131424201120011 is a deficient number, since it is larger than the sum of its proper divisors (23778583621).
131424201120011 is an equidigital number, since it uses as much as digits as its factorization.
131424201120011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23778583620.
The product of its (nonzero) digits is 384, while the sum is 23.
Adding to 131424201120011 its reverse (110021102424131), we get a palindrome (241445303544142).
The spelling of 131424201120011 in words is "one hundred thirty-one trillion, four hundred twenty-four billion, two hundred one million, one hundred twenty thousand, eleven".
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