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13142444323 = 44641294403
BaseRepresentation
bin11000011110101100…
…11100100100100011
31020220220211100100011
430033112130210203
5203403431204243
610012040105351
7643452635131
oct141726344443
936826740304
1013142444323
115634626a38
122669465257
131315a56798
148c9648751
1551dbdc89d
hex30f59c923

13142444323 has 4 divisors (see below), whose sum is σ = 13142783368. Its totient is φ = 13142105280.

The previous prime is 13142444317. The next prime is 13142444333. The reversal of 13142444323 is 32344424131.

13142444323 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13142444323 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13142444333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 102561 + ... + 191842.

It is an arithmetic number, because the mean of its divisors is an integer number (3285695842).

Almost surely, 213142444323 is an apocalyptic number.

13142444323 is a deficient number, since it is larger than the sum of its proper divisors (339045).

13142444323 is an equidigital number, since it uses as much as digits as its factorization.

13142444323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 339044.

The product of its digits is 27648, while the sum is 31.

Adding to 13142444323 its reverse (32344424131), we get a palindrome (45486868454).

The spelling of 13142444323 in words is "thirteen billion, one hundred forty-two million, four hundred forty-four thousand, three hundred twenty-three".

Divisors: 1 44641 294403 13142444323