1314320234131 has 4 divisors (see below), whose sum is σ = 1330957199200. Its totient is φ = 1297683269064.

The previous prime is 1314320234119. The next prime is 1314320234153.

1314320234131 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1314320234131 - 2⁹ = 1314320233619 is a prime.

It is a super-2 number, since 2×1314320234131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1314320234131.

It is not an unprimeable number, because it can be changed into a prime (1314320234191) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8318482416 + ... + 8318482573.

It is an arithmetic number, because the mean of its divisors is an integer number (332739299800).

Almost surely, 2^{1314320234131} is an apocalyptic number.

1314320234131 is a deficient number, since it is larger than the sum of its proper divisors (16636965069).

1314320234131 is an equidigital number, since it uses as much as digits as its factorization.

1314320234131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16636965068.

The product of its (nonzero) digits is 5184, while the sum is 28.

It can be divided in two parts, 1314320 and 234131, that added together give a palindrome (1548451).

The spelling of 1314320234131 in words is "one trillion, three hundred fourteen billion, three hundred twenty million, two hundred thirty-four thousand, one hundred thirty-one".