131433100330041 has 6 divisors (see below), whose sum is σ = 189847811587850. Its totient is φ = 87622066886688.

The previous prime is 131433100330027. The next prime is 131433100330117. The reversal of 131433100330041 is 140033001334131.

131433100330041 is a `hidden beast` number, since 1 + 3 + 1 + 4 + 3 + 310 + 0 + 3 + 300 + 41 = 666.

It can be written as a sum of positive squares in only one way, i.e., 69523978314816 + 61909122015225 = 8338104^2 + 7868235^2 .

It is not a de Polignac number, because 131433100330041 - 2¹⁰ = 131433100329017 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131433100329987 and 131433100330014.

It is not an unprimeable number, because it can be changed into a prime (131433100430041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 7301838907216 + ... + 7301838907233.

Almost surely, 2^{131433100330041} is an apocalyptic number.

It is an amenable number.

131433100330041 is a deficient number, since it is larger than the sum of its proper divisors (58414711257809).

131433100330041 is a wasteful number, since it uses less digits than its factorization.

131433100330041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14603677814455 (or 14603677814452 counting only the distinct ones).

The product of its (nonzero) digits is 3888, while the sum is 27.

Adding to 131433100330041 its reverse (140033001334131), we get a palindrome (271466101664172).

The spelling of 131433100330041 in words is "one hundred thirty-one trillion, four hundred thirty-three billion, one hundred million, three hundred thirty thousand, forty-one".