131433221421121 has 4 divisors (see below), whose sum is σ = 131439933038592. Its totient is φ = 131426509803652.

The previous prime is 131433221421101. The next prime is 131433221421169. The reversal of 131433221421121 is 121124122334131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131433221421121 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131433221421101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3355779361 + ... + 3355818526.

It is an arithmetic number, because the mean of its divisors is an integer number (32859983259648).

Almost surely, 2^{131433221421121} is an apocalyptic number.

It is an amenable number.

131433221421121 is a deficient number, since it is larger than the sum of its proper divisors (6711617471).

131433221421121 is an equidigital number, since it uses as much as digits as its factorization.

131433221421121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6711617470.

The product of its digits is 6912, while the sum is 31.

Adding to 131433221421121 its reverse (121124122334131), we get a palindrome (252557343755252).

The spelling of 131433221421121 in words is "one hundred thirty-one trillion, four hundred thirty-three billion, two hundred twenty-one million, four hundred twenty-one thousand, one hundred twenty-one".