131433240101121 has 40 divisors (see below), whose sum is σ = 227735965645760. Its totient is φ = 73983742807392.

The previous prime is 131433240101101. The next prime is 131433240101197. The reversal of 131433240101121 is 121101042334131.

131433240101121 is a `hidden beast` number, since 1 + 3 + 1 + 433 + 2 + 4 + 0 + 101 + 121 = 666.

It is not a de Polignac number, because 131433240101121 - 2¹⁵ = 131433240068353 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (131433240101101) by changing a digit.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 1729847506 + ... + 1729923483.

It is an arithmetic number, because the mean of its divisors is an integer number (5693399141144).

Almost surely, 2^{131433240101121} is an apocalyptic number.

It is an amenable number.

131433240101121 is a deficient number, since it is larger than the sum of its proper divisors (96302725544639).

131433240101121 is an equidigital number, since it uses as much as digits as its factorization.

131433240101121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3459771075 (or 3459771066 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 27.

Adding to 131433240101121 its reverse (121101042334131), we get a palindrome (252534282435252).

The spelling of 131433240101121 in words is "one hundred thirty-one trillion, four hundred thirty-three billion, two hundred forty million, one hundred one thousand, one hundred twenty-one".