Base | Representation |
---|---|
bin | 11101111000110000000011… |
… | …001010001100011110111011 |
3 | 122020101211221211212212221211 |
4 | 131320300003022030132323 |
5 | 114212031214411143003 |
6 | 1143320104235143551 |
7 | 36454313553335002 |
oct | 3570600312143673 |
9 | 566354854785854 |
10 | 131443232131003 |
11 | 38977841902401 |
12 | 128aa6b45a4bb7 |
13 | 5846074a50060 |
14 | 2465c5a325c39 |
15 | 102e217d3896d |
hex | 778c0328c7bb |
131443232131003 has 16 divisors (see below), whose sum is σ = 142063105113216. Its totient is φ = 120896083768320.
The previous prime is 131443232130997. The next prime is 131443232131031. The reversal of 131443232131003 is 300131232344131.
It is a cyclic number.
It is not a de Polignac number, because 131443232131003 - 25 = 131443232130971 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131443232131033) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 103343251 + ... + 104607427.
It is an arithmetic number, because the mean of its divisors is an integer number (8878944069576).
Almost surely, 2131443232131003 is an apocalyptic number.
131443232131003 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
131443232131003 is a deficient number, since it is larger than the sum of its proper divisors (10619872982213).
131443232131003 is a wasteful number, since it uses less digits than its factorization.
131443232131003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1292934.
The product of its (nonzero) digits is 15552, while the sum is 31.
Adding to 131443232131003 its reverse (300131232344131), we get a palindrome (431574464475134).
The spelling of 131443232131003 in words is "one hundred thirty-one trillion, four hundred forty-three billion, two hundred thirty-two million, one hundred thirty-one thousand, three".
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