13146231435 has 16 divisors (see below), whose sum is σ = 21057705216. Its totient is φ = 7003411808.

The previous prime is 13146231433. The next prime is 13146231437. The reversal of 13146231435 is 53413264131.

13146231435 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (13146231433) and next prime (13146231437).

It is a cyclic number.

It is not a de Polignac number, because 13146231435 - 2¹ = 13146231433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13146231396 and 13146231405.

It is not an unprimeable number, because it can be changed into a prime (13146231433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 480729 + ... + 507338.

It is an arithmetic number, because the mean of its divisors is an integer number (1316106576).

Almost surely, 2^13146231435 is an apocalyptic number.

13146231435 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

13146231435 is a deficient number, since it is larger than the sum of its proper divisors (7911473781).

13146231435 is an equidigital number, since it uses as much as digits as its factorization.

13146231435 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 988962.

The product of its digits is 25920, while the sum is 33.

Adding to 13146231435 its reverse (53413264131), we get a palindrome (66559495566).

The spelling of 13146231435 in words is "thirteen billion, one hundred forty-six million, two hundred thirty-one thousand, four hundred thirty-five".