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131500554121 = 1756591366907
BaseRepresentation
bin111101001111000001…
…0110011011110001001
3110120102111111021220101
41322132002303132021
54123303120212441
6140224401125401
712333464160466
oct1723602633611
9416374437811
10131500554121
11508506a8702
122159b329861
13c528a2c091
1465168b466d
15364996c231
hex1e9e0b3789

131500554121 has 8 divisors (see below), whose sum is σ = 139260587040. Its totient is φ = 123743266368.

The previous prime is 131500554071. The next prime is 131500554137. The reversal of 131500554121 is 121455005131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 131500554121 - 29 = 131500553609 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 131500554121.

It is not an unprimeable number, because it can be changed into a prime (131500554161) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 587251 + ... + 779656.

It is an arithmetic number, because the mean of its divisors is an integer number (17407573380).

Almost surely, 2131500554121 is an apocalyptic number.

It is an amenable number.

131500554121 is a deficient number, since it is larger than the sum of its proper divisors (7760032919).

131500554121 is a wasteful number, since it uses less digits than its factorization.

131500554121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1372583.

The product of its (nonzero) digits is 3000, while the sum is 28.

Adding to 131500554121 its reverse (121455005131), we get a palindrome (252955559252).

The spelling of 131500554121 in words is "one hundred thirty-one billion, five hundred million, five hundred fifty-four thousand, one hundred twenty-one".

Divisors: 1 17 5659 96203 1366907 23237419 7735326713 131500554121