13150094435 has 4 divisors (see below), whose sum is σ = 15780113328. Its totient is φ = 10520075544.

The previous prime is 13150094431. The next prime is 13150094449. The reversal of 13150094435 is 53449005131.

13150094435 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13150094435 - 2² = 13150094431 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13150094395 and 13150094404.

It is not an unprimeable number, because it can be changed into a prime (13150094431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1315009439 + ... + 1315009448.

It is an arithmetic number, because the mean of its divisors is an integer number (3945028332).

Almost surely, 2^13150094435 is an apocalyptic number.

13150094435 is a deficient number, since it is larger than the sum of its proper divisors (2630018893).

13150094435 is an equidigital number, since it uses as much as digits as its factorization.

13150094435 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2630018892.

The product of its (nonzero) digits is 32400, while the sum is 35.

Adding to 13150094435 its reverse (53449005131), we get a palindrome (66599099566).

The spelling of 13150094435 in words is "thirteen billion, one hundred fifty million, ninety-four thousand, four hundred thirty-five".