13150154101033 has 4 divisors (see below), whose sum is σ = 13150778328400. Its totient is φ = 13149529873668.

The previous prime is 13150154100991. The next prime is 13150154101037. The reversal of 13150154101033 is 33010145105131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13150154101033 is a prime.

It is a super-3 number, since 3×13150154101033³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13150154100992 and 13150154101010.

It is not an unprimeable number, because it can be changed into a prime (13150154101037) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 312082083 + ... + 312124216.

It is an arithmetic number, because the mean of its divisors is an integer number (3287694582100).

Almost surely, 2^{13150154101033} is an apocalyptic number.

It is an amenable number.

13150154101033 is a deficient number, since it is larger than the sum of its proper divisors (624227367).

13150154101033 is an equidigital number, since it uses as much as digits as its factorization.

13150154101033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 624227366.

The product of its (nonzero) digits is 2700, while the sum is 28.

Adding to 13150154101033 its reverse (33010145105131), we get a palindrome (46160299206164).

The spelling of 13150154101033 in words is "thirteen trillion, one hundred fifty billion, one hundred fifty-four million, one hundred one thousand, thirty-three".