131511202041 has 4 divisors (see below), whose sum is σ = 175348269392. Its totient is φ = 87674134692.

The previous prime is 131511201973. The next prime is 131511202051. The reversal of 131511202041 is 140202115131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 131511202041 - 2⁹ = 131511201529 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131511201999 and 131511202017.

It is not an unprimeable number, because it can be changed into a prime (131511202051) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21918533671 + ... + 21918533676.

It is an arithmetic number, because the mean of its divisors is an integer number (43837067348).

Almost surely, 2^131511202041 is an apocalyptic number.

It is an amenable number.

131511202041 is a deficient number, since it is larger than the sum of its proper divisors (43837067351).

131511202041 is an equidigital number, since it uses as much as digits as its factorization.

131511202041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43837067350.

The product of its (nonzero) digits is 240, while the sum is 21.

Adding to 131511202041 its reverse (140202115131), we get a palindrome (271713317172).

The spelling of 131511202041 in words is "one hundred thirty-one billion, five hundred eleven million, two hundred two thousand, forty-one".