131525441342035 has 8 divisors (see below), whose sum is σ = 169971339580560. Its totient is φ = 97126479760224.

The previous prime is 131525441342021. The next prime is 131525441342063. The reversal of 131525441342035 is 530243144525131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 131525441342035 - 2³⁵ = 131491081603667 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131525441341982 and 131525441342000.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1011734164105 + ... + 1011734164234.

It is an arithmetic number, because the mean of its divisors is an integer number (21246417447570).

Almost surely, 2^{131525441342035} is an apocalyptic number.

131525441342035 is a deficient number, since it is larger than the sum of its proper divisors (38445898238525).

131525441342035 is a wasteful number, since it uses less digits than its factorization.

131525441342035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2023468328357.

The product of its (nonzero) digits is 864000, while the sum is 43.

Adding to 131525441342035 its reverse (530243144525131), we get a palindrome (661768585867166).

The spelling of 131525441342035 in words is "one hundred thirty-one trillion, five hundred twenty-five billion, four hundred forty-one million, three hundred forty-two thousand, thirty-five".