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1315364621641 = 7187909231663
BaseRepresentation
bin10011001001000001110…
…101110100110101001001
311122202012000121002202221
4103021001311310311021
5133022331320343031
62444134204454041
7164013650543560
oct23110165646511
94582160532687
101315364621641
11467930045904
12192b14b4a321
1397066348a35
1447941da4bd7
1524337c60a11
hex13241d74d49

1315364621641 has 4 divisors (see below), whose sum is σ = 1503273853312. Its totient is φ = 1127455389972.

The previous prime is 1315364621591. The next prime is 1315364621671. The reversal of 1315364621641 is 1461264635131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1315364621641 - 219 = 1315364097353 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1315364621671) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 93954615825 + ... + 93954615838.

It is an arithmetic number, because the mean of its divisors is an integer number (375818463328).

Almost surely, 21315364621641 is an apocalyptic number.

It is an amenable number.

1315364621641 is a deficient number, since it is larger than the sum of its proper divisors (187909231671).

1315364621641 is an equidigital number, since it uses as much as digits as its factorization.

1315364621641 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 187909231670.

The product of its digits is 311040, while the sum is 43.

The spelling of 1315364621641 in words is "one trillion, three hundred fifteen billion, three hundred sixty-four million, six hundred twenty-one thousand, six hundred forty-one".

Divisors: 1 7 187909231663 1315364621641