Base | Representation |
---|---|
bin | 1011111101101011101000… |
… | …1111011000100111111001 |
3 | 1201120112120210101002111212 |
4 | 2333122322033120213321 |
5 | 3211010014000034140 |
6 | 43551001510532505 |
7 | 2525240114003264 |
oct | 277327217304771 |
9 | 51515523332455 |
10 | 13154314455545 |
11 | 421179363a18a |
12 | 1585489367135 |
13 | 7455a6048943 |
14 | 33695a7c3cdb |
15 | 17c291e03765 |
hex | bf6ba3d89f9 |
13154314455545 has 4 divisors (see below), whose sum is σ = 15785177346660. Its totient is φ = 10523451564432.
The previous prime is 13154314455397. The next prime is 13154314455551. The reversal of 13154314455545 is 54555441345131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 5509028625424 + 7645285830121 = 2347132^2 + 2765011^2 .
It is a cyclic number.
It is not a de Polignac number, because 13154314455545 - 222 = 13154310261241 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13154314455493 and 13154314455502.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1315431445550 + ... + 1315431445559.
It is an arithmetic number, because the mean of its divisors is an integer number (3946294336665).
Almost surely, 213154314455545 is an apocalyptic number.
It is an amenable number.
13154314455545 is a deficient number, since it is larger than the sum of its proper divisors (2630862891115).
13154314455545 is an equidigital number, since it uses as much as digits as its factorization.
13154314455545 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2630862891114.
The product of its digits is 7200000, while the sum is 50.
The spelling of 13154314455545 in words is "thirteen trillion, one hundred fifty-four billion, three hundred fourteen million, four hundred fifty-five thousand, five hundred forty-five".
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