131544114053251 has 4 divisors (see below), whose sum is σ = 131643844239600. Its totient is φ = 131444383866904.

The previous prime is 131544114053239. The next prime is 131544114053299. The reversal of 131544114053251 is 152350411445131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131544114053251 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131544114023251) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 49865091196 + ... + 49865093833.

It is an arithmetic number, because the mean of its divisors is an integer number (32910961059900).

Almost surely, 2^{131544114053251} is an apocalyptic number.

131544114053251 is a deficient number, since it is larger than the sum of its proper divisors (99730186349).

131544114053251 is an equidigital number, since it uses as much as digits as its factorization.

131544114053251 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 99730186348.

The product of its (nonzero) digits is 144000, while the sum is 40.

Adding to 131544114053251 its reverse (152350411445131), we get a palindrome (283894525498382).

The spelling of 131544114053251 in words is "one hundred thirty-one trillion, five hundred forty-four billion, one hundred fourteen million, fifty-three thousand, two hundred fifty-one".