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13155156520321 = 40222332706127
BaseRepresentation
bin1011111101101110110001…
…1011100110110110000001
31201120121202110212102020011
42333123230123212312001
53211013230032122241
643551221231144521
72525300020304524
oct277335433466601
951517673772204
1013155156520321
1142120859a0992
121585683375141
137456ab63911a
143369da57cbbb
1517c2e0cd9281
hexbf6ec6e6d81

13155156520321 has 4 divisors (see below), whose sum is σ = 13155189628672. Its totient is φ = 13155123411972.

The previous prime is 13155156520277. The next prime is 13155156520399. The reversal of 13155156520321 is 12302565155131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13155156520321 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13155156520621) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15950841 + ... + 16755286.

It is an arithmetic number, because the mean of its divisors is an integer number (3288797407168).

Almost surely, 213155156520321 is an apocalyptic number.

It is an amenable number.

13155156520321 is a deficient number, since it is larger than the sum of its proper divisors (33108351).

13155156520321 is an equidigital number, since it uses as much as digits as its factorization.

13155156520321 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 33108350.

The product of its (nonzero) digits is 135000, while the sum is 40.

The spelling of 13155156520321 in words is "thirteen trillion, one hundred fifty-five billion, one hundred fifty-six million, five hundred twenty thousand, three hundred twenty-one".

Divisors: 1 402223 32706127 13155156520321