Base | Representation |
---|---|
bin | 111101010000100110… |
… | …0000000010010000001 |
3 | 110120120011201221021020 |
4 | 1322201030000102001 |
5 | 4123410121010122 |
6 | 140233523420053 |
7 | 12335004402414 |
oct | 1724114002201 |
9 | 416504657236 |
10 | 131553297537 |
11 | 50878452602 |
12 | 215b4b24629 |
13 | c5369380bc |
14 | 651d8c3b7b |
15 | 364e3d9c5c |
hex | 1ea1300481 |
131553297537 has 4 divisors (see below), whose sum is σ = 175404396720. Its totient is φ = 87702198356.
The previous prime is 131553297527. The next prime is 131553297569. The reversal of 131553297537 is 735792355131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 131553297537 - 24 = 131553297521 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 131553297537.
It is not an unprimeable number, because it can be changed into a prime (131553297527) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21925549587 + ... + 21925549592.
It is an arithmetic number, because the mean of its divisors is an integer number (43851099180).
Almost surely, 2131553297537 is an apocalyptic number.
It is an amenable number.
131553297537 is a deficient number, since it is larger than the sum of its proper divisors (43851099183).
131553297537 is an equidigital number, since it uses as much as digits as its factorization.
131553297537 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 43851099182.
The product of its digits is 2976750, while the sum is 51.
The spelling of 131553297537 in words is "one hundred thirty-one billion, five hundred fifty-three million, two hundred ninety-seven thousand, five hundred thirty-seven".
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