Base | Representation |
---|---|
bin | 1011111101101111100000… |
… | …1110001101100010101001 |
3 | 1201120122021021002110111121 |
4 | 2333123320032031202221 |
5 | 3211014131202213101 |
6 | 43551253015055241 |
7 | 2525304641562055 |
oct | 277337016154251 |
9 | 51518237073447 |
10 | 13155354335401 |
11 | 4212177621323 |
12 | 1585719671521 |
13 | 745710609a75 |
14 | 336a18952c65 |
15 | 17c3033610a1 |
hex | bf6f838d8a9 |
13155354335401 has 8 divisors (see below), whose sum is σ = 13511424751880. Its totient is φ = 12799311303168.
The previous prime is 13155354335369. The next prime is 13155354335443. The reversal of 13155354335401 is 10453345355131.
It can be written as a sum of positive squares in 4 ways, for example, as 1836705273001 + 11318649062400 = 1355251^2 + 3364320^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13155354335401 - 25 = 13155354335369 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13155354335701) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5870406 + ... + 7795663.
It is an arithmetic number, because the mean of its divisors is an integer number (1688928093985).
Almost surely, 213155354335401 is an apocalyptic number.
It is an amenable number.
13155354335401 is a deficient number, since it is larger than the sum of its proper divisors (356070416479).
13155354335401 is a wasteful number, since it uses less digits than its factorization.
13155354335401 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13692123.
The product of its (nonzero) digits is 810000, while the sum is 43.
The spelling of 13155354335401 in words is "thirteen trillion, one hundred fifty-five billion, three hundred fifty-four million, three hundred thirty-five thousand, four hundred one".
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