Base | Representation |
---|---|
bin | 10011001001001100111… |
… | …011000110101111111011 |
3 | 11122202122222110111120111 |
4 | 103021030323012233323 |
5 | 133023221420231011 |
6 | 2444204450005151 |
7 | 164021366133661 |
oct | 23111473065773 |
9 | 4582588414514 |
10 | 1315550555131 |
11 | 467a15aa044a |
12 | 192b672767b7 |
13 | 97095a19557 |
14 | 4795c964c31 |
15 | 2434923c121 |
hex | 1324cec6bfb |
1315550555131 has 8 divisors (see below), whose sum is σ = 1316475975744. Its totient is φ = 1314625267200.
The previous prime is 1315550555093. The next prime is 1315550555147.
1315550555131 is nontrivially palindromic in base 10.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1315550555131 - 213 = 1315550546939 is a prime.
It is a super-2 number, since 2×13155505551312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1315550555191) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 27726430 + ... + 27773836.
It is an arithmetic number, because the mean of its divisors is an integer number (164559496968).
Almost surely, 21315550555131 is an apocalyptic number.
1315550555131 is a deficient number, since it is larger than the sum of its proper divisors (925420613).
1315550555131 is a wasteful number, since it uses less digits than its factorization.
1315550555131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 66341.
The product of its (nonzero) digits is 140625, while the sum is 40.
The spelling of 1315550555131 in words is "one trillion, three hundred fifteen billion, five hundred fifty million, five hundred fifty-five thousand, one hundred thirty-one".
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