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1315550555131 = 16011733347407
BaseRepresentation
bin10011001001001100111…
…011000110101111111011
311122202122222110111120111
4103021030323012233323
5133023221420231011
62444204450005151
7164021366133661
oct23111473065773
94582588414514
101315550555131
11467a15aa044a
12192b672767b7
1397095a19557
144795c964c31
152434923c121
hex1324cec6bfb

1315550555131 has 8 divisors (see below), whose sum is σ = 1316475975744. Its totient is φ = 1314625267200.

The previous prime is 1315550555093. The next prime is 1315550555147.

1315550555131 is nontrivially palindromic in base 10.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1315550555131 - 213 = 1315550546939 is a prime.

It is a super-2 number, since 2×13155505551312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1315550555191) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 27726430 + ... + 27773836.

It is an arithmetic number, because the mean of its divisors is an integer number (164559496968).

Almost surely, 21315550555131 is an apocalyptic number.

1315550555131 is a deficient number, since it is larger than the sum of its proper divisors (925420613).

1315550555131 is a wasteful number, since it uses less digits than its factorization.

1315550555131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 66341.

The product of its (nonzero) digits is 140625, while the sum is 40.

The spelling of 1315550555131 in words is "one trillion, three hundred fifteen billion, five hundred fifty million, five hundred fifty-five thousand, one hundred thirty-one".

Divisors: 1 1601 17333 47407 27750133 75898607 821705531 1315550555131