Base | Representation |
---|---|
bin | 1011111101110000001001… |
… | …0001101000000010111001 |
3 | 1201120122201000110122100011 |
4 | 2333130002101220002321 |
5 | 3211020002342040203 |
6 | 43551321442141521 |
7 | 2525312060330041 |
oct | 277340221500271 |
9 | 51518630418304 |
10 | 13155523002553 |
11 | 4212253853468 |
12 | 15857660518a1 |
13 | 745739543509 |
14 | 336a330da721 |
15 | 17c31307b76d |
hex | bf7024680b9 |
13155523002553 has 16 divisors (see below), whose sum is σ = 13247198502912. Its totient is φ = 13064104512000.
The previous prime is 13155523002527. The next prime is 13155523002667. The reversal of 13155523002553 is 35520032555131.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13155523002553 is a prime.
It is a super-2 number, since 2×131555230025532 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13155523012553) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 268504888 + ... + 268553878.
It is an arithmetic number, because the mean of its divisors is an integer number (827949906432).
Almost surely, 213155523002553 is an apocalyptic number.
It is an amenable number.
13155523002553 is a deficient number, since it is larger than the sum of its proper divisors (91675500359).
13155523002553 is a wasteful number, since it uses less digits than its factorization.
13155523002553 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 51576.
The product of its (nonzero) digits is 337500, while the sum is 40.
Adding to 13155523002553 its reverse (35520032555131), we get a palindrome (48675555557684).
The spelling of 13155523002553 in words is "thirteen trillion, one hundred fifty-five billion, five hundred twenty-three million, two thousand, five hundred fifty-three".
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