Base | Representation |
---|---|
bin | 111101010010001001… |
… | …1010011010110001011 |
3 | 110120200211001020120211 |
4 | 1322210103103112023 |
5 | 4124012004323113 |
6 | 140243031301551 |
7 | 12336210436435 |
oct | 1724423232613 |
9 | 416624036524 |
10 | 131605542283 |
11 | 508a4996886 |
12 | 2160a51a8b7 |
13 | c5446cb157 |
14 | 6526803655 |
15 | 3653ca9b3d |
hex | 1ea44d358b |
131605542283 has 4 divisors (see below), whose sum is σ = 131608577520. Its totient is φ = 131602507048.
The previous prime is 131605542281. The next prime is 131605542307. The reversal of 131605542283 is 382245506131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131605542283 - 21 = 131605542281 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131605542281) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1451623 + ... + 1539616.
It is an arithmetic number, because the mean of its divisors is an integer number (32902144380).
Almost surely, 2131605542283 is an apocalyptic number.
131605542283 is a deficient number, since it is larger than the sum of its proper divisors (3035237).
131605542283 is an equidigital number, since it uses as much as digits as its factorization.
131605542283 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3035236.
The product of its (nonzero) digits is 172800, while the sum is 40.
The spelling of 131605542283 in words is "one hundred thirty-one billion, six hundred five million, five hundred forty-two thousand, two hundred eighty-three".
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