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13162534522531 = 16380751745537
BaseRepresentation
bin1011111110001010010000…
…1100011100111010100011
31201121022210122212202120021
42333202210030130322203
53211123332314210111
643554441311254311
72525650606266202
oct277424414347243
951538718782507
1013162534522531
114215221656179
121586ba221a397
137462b6050ac4
143370da3b5239
1517c5c38bdd71
hexbf8a431cea3

13162534522531 has 4 divisors (see below), whose sum is σ = 13243286268232. Its totient is φ = 13081782776832.

The previous prime is 13162534522483. The next prime is 13162534522537. The reversal of 13162534522531 is 13522543526131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13162534522531 - 221 = 13162532425379 is a prime.

It is a super-2 number, since 2×131625345225312 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13162534522537) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40375872606 + ... + 40375872931.

It is an arithmetic number, because the mean of its divisors is an integer number (3310821567058).

Almost surely, 213162534522531 is an apocalyptic number.

13162534522531 is a deficient number, since it is larger than the sum of its proper divisors (80751745701).

13162534522531 is an equidigital number, since it uses as much as digits as its factorization.

13162534522531 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 80751745700.

The product of its digits is 648000, while the sum is 43.

The spelling of 13162534522531 in words is "thirteen trillion, one hundred sixty-two billion, five hundred thirty-four million, five hundred twenty-two thousand, five hundred thirty-one".

Divisors: 1 163 80751745537 13162534522531