Base | Representation |
---|---|
bin | 10011001001111111101… |
… | …100011101110010000011 |
3 | 11122211212100021102210001 |
4 | 103021333230131302003 |
5 | 133031443000332311 |
6 | 2444425155020431 |
7 | 164051451253330 |
oct | 23117754356203 |
9 | 4584770242701 |
10 | 1316402355331 |
11 | 4683128a1558 |
12 | 19316459a717 |
13 | 971a033803b |
14 | 479ddb35987 |
15 | 24398de74c1 |
hex | 1327fb1dc83 |
1316402355331 has 4 divisors (see below), whose sum is σ = 1504459834672. Its totient is φ = 1128344875992.
The previous prime is 1316402355269. The next prime is 1316402355347. The reversal of 1316402355331 is 1335532046131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1316402355331 - 217 = 1316402224259 is a prime.
It is a super-2 number, since 2×13164023553312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1316402355431) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 94028739660 + ... + 94028739673.
It is an arithmetic number, because the mean of its divisors is an integer number (376114958668).
Almost surely, 21316402355331 is an apocalyptic number.
1316402355331 is a deficient number, since it is larger than the sum of its proper divisors (188057479341).
1316402355331 is an equidigital number, since it uses as much as digits as its factorization.
1316402355331 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 188057479340.
The product of its (nonzero) digits is 97200, while the sum is 37.
The spelling of 1316402355331 in words is "one trillion, three hundred sixteen billion, four hundred two million, three hundred fifty-five thousand, three hundred thirty-one".
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