Base | Representation |
---|---|
bin | 111101010101100010… |
… | …0010010100100011011 |
3 | 110120222201121220101221 |
4 | 1322223010102210123 |
5 | 4124230034004301 |
6 | 140302204152511 |
7 | 12342056300335 |
oct | 1725304224433 |
9 | 416881556357 |
10 | 131719047451 |
11 | 50952a71a02 |
12 | 21640538737 |
13 | c56208ca84 |
14 | 653790c455 |
15 | 365dc2ada1 |
hex | 1eab11291b |
131719047451 has 4 divisors (see below), whose sum is σ = 136261083600. Its totient is φ = 127177011304.
The previous prime is 131719047443. The next prime is 131719047457. The reversal of 131719047451 is 154740917131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131719047451 - 23 = 131719047443 is a prime.
It is a super-2 number, since 2×1317190474512 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 131719047398 and 131719047407.
It is not an unprimeable number, because it can be changed into a prime (131719047457) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2271018031 + ... + 2271018088.
It is an arithmetic number, because the mean of its divisors is an integer number (34065270900).
Almost surely, 2131719047451 is an apocalyptic number.
131719047451 is a deficient number, since it is larger than the sum of its proper divisors (4542036149).
131719047451 is an equidigital number, since it uses as much as digits as its factorization.
131719047451 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4542036148.
The product of its (nonzero) digits is 105840, while the sum is 43.
The spelling of 131719047451 in words is "one hundred thirty-one billion, seven hundred nineteen million, forty-seven thousand, four hundred fifty-one".
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