Base | Representation |
---|---|
bin | 1011111110101111010010… |
… | …1001111100111010011011 |
3 | 1201122021110101110012200211 |
4 | 2333223310221330322123 |
5 | 3211304211414231033 |
6 | 44003203504511551 |
7 | 2526452123500363 |
oct | 277536451747233 |
9 | 51567411405624 |
10 | 13172474367643 |
11 | 42194624139a8 |
12 | 1588ab701b5b7 |
13 | 74720b438966 |
14 | 3377a05599a3 |
15 | 17c9a63482cd |
hex | bfaf4a7ce9b |
13172474367643 has 16 divisors (see below), whose sum is σ = 13577913778176. Its totient is φ = 12771549564480.
The previous prime is 13172474367631. The next prime is 13172474367673. The reversal of 13172474367643 is 34676347427131.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13172474367643 is a prime.
It is a super-3 number, since 3×131724743676433 (a number of 40 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13172474367673) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 139398630 + ... + 139493092.
It is an arithmetic number, because the mean of its divisors is an integer number (848619611136).
Almost surely, 213172474367643 is an apocalyptic number.
13172474367643 is a deficient number, since it is larger than the sum of its proper divisors (405439410533).
13172474367643 is a wasteful number, since it uses less digits than its factorization.
13172474367643 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 118314.
The product of its digits is 42674688, while the sum is 58.
The spelling of 13172474367643 in words is "thirteen trillion, one hundred seventy-two billion, four hundred seventy-four million, three hundred sixty-seven thousand, six hundred forty-three".
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