Base | Representation |
---|---|
bin | 111101010110001010… |
… | …1110111101011011001 |
3 | 110121001012212102000111 |
4 | 1322230111313223121 |
5 | 4124301022324423 |
6 | 140304250404321 |
7 | 12342436130242 |
oct | 1725425675331 |
9 | 417035772014 |
10 | 131740433113 |
11 | 50964049303 |
12 | 216477306a1 |
13 | c566639b03 |
14 | 653a6b7cc9 |
15 | 3660a5260d |
hex | 1eac577ad9 |
131740433113 has 8 divisors (see below), whose sum is σ = 132049348200. Its totient is φ = 131431587840.
The previous prime is 131740433053. The next prime is 131740433141. The reversal of 131740433113 is 311334047131.
It can be written as a sum of positive squares in 4 ways, for example, as 48517991824 + 83222441289 = 220268^2 + 288483^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 131740433113 - 217 = 131740302041 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131740430113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6894733 + ... + 6913813.
It is an arithmetic number, because the mean of its divisors is an integer number (16506168525).
Almost surely, 2131740433113 is an apocalyptic number.
It is an amenable number.
131740433113 is a deficient number, since it is larger than the sum of its proper divisors (308915087).
131740433113 is a wasteful number, since it uses less digits than its factorization.
131740433113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 34907.
The product of its (nonzero) digits is 9072, while the sum is 31.
The spelling of 131740433113 in words is "one hundred thirty-one billion, seven hundred forty million, four hundred thirty-three thousand, one hundred thirteen".
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