Base | Representation |
---|---|
bin | 11101111101001000001100… |
… | …100100100101111100001011 |
3 | 122021110121101111201221101002 |
4 | 131331020030210211330023 |
5 | 114231443242131203213 |
6 | 1144110213031445215 |
7 | 36515123033064302 |
oct | 3575101444457413 |
9 | 567417344657332 |
10 | 131744037756683 |
11 | 38a83372832150 |
12 | 12938a6382680b |
13 | 5868542751341 |
14 | 2476634459439 |
15 | 1036e710d1658 |
hex | 77d20c925f0b |
131744037756683 has 8 divisors (see below), whose sum is σ = 143721375411456. Its totient is φ = 119766801260200.
The previous prime is 131744037756673. The next prime is 131744037756769. The reversal of 131744037756683 is 386657730447131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 131744037756683 - 218 = 131744037494539 is a prime.
It is a super-2 number, since 2×1317440377566832 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131744037756673) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 22553591 + ... + 27787632.
It is an arithmetic number, because the mean of its divisors is an integer number (17965171926432).
Almost surely, 2131744037756683 is an apocalyptic number.
131744037756683 is a deficient number, since it is larger than the sum of its proper divisors (11977337654773).
131744037756683 is a wasteful number, since it uses less digits than its factorization.
131744037756683 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 50579145.
The product of its (nonzero) digits is 213373440, while the sum is 65.
The spelling of 131744037756683 in words is "one hundred thirty-one trillion, seven hundred forty-four billion, thirty-seven million, seven hundred fifty-six thousand, six hundred eighty-three".
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