1317522433 has 4 divisors (see below), whose sum is σ = 1322532288. Its totient is φ = 1312512580.

The previous prime is 1317522397. The next prime is 1317522439. The reversal of 1317522433 is 3342257131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1317522433 - 2²¹ = 1315425281 is a prime.

It is a super-2 number, since 2×1317522433² = 3471730722916478978, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1317522395 and 1317522404.

It is not an unprimeable number, because it can be changed into a prime (1317522439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2504533 + ... + 2505058.

It is an arithmetic number, because the mean of its divisors is an integer number (330633072).

Almost surely, 2^1317522433 is an apocalyptic number.

It is an amenable number.

1317522433 is a deficient number, since it is larger than the sum of its proper divisors (5009855).

1317522433 is an equidigital number, since it uses as much as digits as its factorization.

1317522433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5009854.

The product of its digits is 15120, while the sum is 31.

The square root of 1317522433 is about 36297.6918412177. The cubic root of 1317522433 is about 1096.2745687436.

Adding to 1317522433 its reverse (3342257131), we get a palindrome (4659779564).

The spelling of 1317522433 in words is "one billion, three hundred seventeen million, five hundred twenty-two thousand, four hundred thirty-three".