Base | Representation |
---|---|
bin | 11101111101101011010110… |
… | …100000100101011000001011 |
3 | 122021121012211012200000200221 |
4 | 131331223112200211120023 |
5 | 114233103044033114203 |
6 | 1144135414431410511 |
7 | 36520630331110360 |
oct | 3575532640453013 |
9 | 567535735600627 |
10 | 131781785441803 |
11 | 38a98383379732 |
12 | 12944239383a37 |
13 | 586bc79cb62b3 |
14 | 24783b584c467 |
15 | 1037e2eeb5abd |
hex | 77dad682560b |
131781785441803 has 4 divisors (see below), whose sum is σ = 150607754790640. Its totient is φ = 112955816092968.
The previous prime is 131781785441771. The next prime is 131781785441861. The reversal of 131781785441803 is 308144587187131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131781785441803 - 25 = 131781785441771 is a prime.
It is a super-2 number, since 2×1317817854418032 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (131781785441503) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9412984674408 + ... + 9412984674421.
It is an arithmetic number, because the mean of its divisors is an integer number (37651938697660).
Almost surely, 2131781785441803 is an apocalyptic number.
131781785441803 is a deficient number, since it is larger than the sum of its proper divisors (18825969348837).
131781785441803 is an equidigital number, since it uses as much as digits as its factorization.
131781785441803 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 18825969348836.
The product of its (nonzero) digits is 18063360, while the sum is 61.
The spelling of 131781785441803 in words is "one hundred thirty-one trillion, seven hundred eighty-one billion, seven hundred eighty-five million, four hundred forty-one thousand, eight hundred three".
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