Base | Representation |
---|---|
bin | 10011001011101000101… |
… | …101001100101111000011 |
3 | 11200000102010102011000220 |
4 | 103023220231030233003 |
5 | 133044100010432311 |
6 | 2445320052314123 |
7 | 164143223310432 |
oct | 23135055145703 |
9 | 4600363364026 |
10 | 1318164155331 |
11 | 469037334a11 |
12 | 193576612943 |
13 | 973c134194a |
14 | 47b29b07119 |
15 | 2444d907206 |
hex | 132e8b4cbc3 |
1318164155331 has 4 divisors (see below), whose sum is σ = 1757552207112. Its totient is φ = 878776103552.
The previous prime is 1318164155327. The next prime is 1318164155449. The reversal of 1318164155331 is 1335514618131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1318164155331 - 22 = 1318164155327 is a prime.
It is a super-2 number, since 2×13181641553312 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1318164175331) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 219694025886 + ... + 219694025891.
It is an arithmetic number, because the mean of its divisors is an integer number (439388051778).
Almost surely, 21318164155331 is an apocalyptic number.
1318164155331 is a deficient number, since it is larger than the sum of its proper divisors (439388051781).
1318164155331 is an equidigital number, since it uses as much as digits as its factorization.
1318164155331 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 439388051780.
The product of its digits is 129600, while the sum is 42.
The spelling of 1318164155331 in words is "one trillion, three hundred eighteen billion, one hundred sixty-four million, one hundred fifty-five thousand, three hundred thirty-one".
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