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13185748945 = 52637149789
BaseRepresentation
bin11000100011110111…
…01000111111010001
31021000221022110010001
430101323220333101
5204001022431240
610020224210001
7644520005515
oct142173507721
937027273101
1013185748945
115657014386
12267ba69901
131321a09515
148d12bc145
155228e389a
hex311ee8fd1

13185748945 has 4 divisors (see below), whose sum is σ = 15822898740. Its totient is φ = 10548599152.

The previous prime is 13185748943. The next prime is 13185748973. The reversal of 13185748945 is 54984758131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2966763024 + 10218985921 = 54468^2 + 101089^2 .

It is a cyclic number.

It is not a de Polignac number, because 13185748945 - 21 = 13185748943 is a prime.

It is a super-2 number, since 2×131857489452 (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (13185748943) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1318574890 + ... + 1318574899.

It is an arithmetic number, because the mean of its divisors is an integer number (3955724685).

Almost surely, 213185748945 is an apocalyptic number.

It is an amenable number.

13185748945 is a deficient number, since it is larger than the sum of its proper divisors (2637149795).

13185748945 is an equidigital number, since it uses as much as digits as its factorization.

13185748945 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2637149794.

The product of its digits is 4838400, while the sum is 55.

The spelling of 13185748945 in words is "thirteen billion, one hundred eighty-five million, seven hundred forty-eight thousand, nine hundred forty-five".

Divisors: 1 5 2637149789 13185748945