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131858042113 = 718836863159
BaseRepresentation
bin111101011001101011…
…0100000110100000001
3110121100102011120020101
41322303112200310001
54130021124321423
6140324051242401
712345364602520
oct1726326406401
9417312146211
10131858042113
1150a14477726
122167aba9401
13c584b07635
14654c1704b7
15366b0347ad
hex1eb35a0d01

131858042113 has 4 divisors (see below), whose sum is σ = 150694905280. Its totient is φ = 113021178948.

The previous prime is 131858042083. The next prime is 131858042143. The reversal of 131858042113 is 311240858131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (131858042083) and next prime (131858042143).

It is a cyclic number.

It is not a de Polignac number, because 131858042113 - 213 = 131858033921 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131858042143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9418431573 + ... + 9418431586.

It is an arithmetic number, because the mean of its divisors is an integer number (37673726320).

Almost surely, 2131858042113 is an apocalyptic number.

It is an amenable number.

131858042113 is a deficient number, since it is larger than the sum of its proper divisors (18836863167).

131858042113 is an equidigital number, since it uses as much as digits as its factorization.

131858042113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18836863166.

The product of its (nonzero) digits is 23040, while the sum is 37.

The spelling of 131858042113 in words is "one hundred thirty-one billion, eight hundred fifty-eight million, forty-two thousand, one hundred thirteen".

Divisors: 1 7 18836863159 131858042113