13200041113003 has 4 divisors (see below), whose sum is σ = 13556798980960. Its totient is φ = 12843283245048.

The previous prime is 13200041112991. The next prime is 13200041113019. The reversal of 13200041113003 is 30031114000231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13200041113003 - 2⁵ = 13200041112971 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13200041111003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 178378933923 + ... + 178378933996.

It is an arithmetic number, because the mean of its divisors is an integer number (3389199745240).

Almost surely, 2^{13200041113003} is an apocalyptic number.

13200041113003 is a deficient number, since it is larger than the sum of its proper divisors (356757867957).

13200041113003 is an equidigital number, since it uses as much as digits as its factorization.

13200041113003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 356757867956.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 13200041113003 its reverse (30031114000231), we get a palindrome (43231155113234).

The spelling of 13200041113003 in words is "thirteen trillion, two hundred billion, forty-one million, one hundred thirteen thousand, three".