Search a number
-
+
13200100323 = 34400033441
BaseRepresentation
bin11000100101100100…
…11000101111100011
31021001221022120111120
430102302120233203
5204013211202243
610021455543323
7645053000334
oct142262305743
937057276446
1013200100323
115664126823
12268482ab43
131324992867
148d317628b
15523ccac83
hex312c98be3

13200100323 has 4 divisors (see below), whose sum is σ = 17600133768. Its totient is φ = 8800066880.

The previous prime is 13200100321. The next prime is 13200100351. The reversal of 13200100323 is 32300100231.

13200100323 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13200100323 - 21 = 13200100321 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13200100321) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2200016718 + ... + 2200016723.

It is an arithmetic number, because the mean of its divisors is an integer number (4400033442).

Almost surely, 213200100323 is an apocalyptic number.

13200100323 is a deficient number, since it is larger than the sum of its proper divisors (4400033445).

13200100323 is an equidigital number, since it uses as much as digits as its factorization.

13200100323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4400033444.

The product of its (nonzero) digits is 108, while the sum is 15.

Adding to 13200100323 its reverse (32300100231), we get a palindrome (45500200554).

The spelling of 13200100323 in words is "thirteen billion, two hundred million, one hundred thousand, three hundred twenty-three".

Divisors: 1 3 4400033441 13200100323