13200102020033 has 4 divisors (see below), whose sum is σ = 13200111650388. Its totient is φ = 13200092389680.

The previous prime is 13200102019931. The next prime is 13200102020047. The reversal of 13200102020033 is 33002020100231.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 744334111504 + 12455767908529 = 862748^2 + 3529273^2 .

It is a cyclic number.

It is not a de Polignac number, because 13200102020033 - 2¹⁶ = 13200101954497 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13200102019993 and 13200102020020.

It is not an unprimeable number, because it can be changed into a prime (13200102820033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2332466 + ... + 5642747.

It is an arithmetic number, because the mean of its divisors is an integer number (3300027912597).

Almost surely, 2^{13200102020033} is an apocalyptic number.

It is an amenable number.

13200102020033 is a deficient number, since it is larger than the sum of its proper divisors (9630355).

13200102020033 is an equidigital number, since it uses as much as digits as its factorization.

13200102020033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9630354.

The product of its (nonzero) digits is 216, while the sum is 17.

Adding to 13200102020033 its reverse (33002020100231), we get a palindrome (46202122120264).

The spelling of 13200102020033 in words is "thirteen trillion, two hundred billion, one hundred two million, twenty thousand, thirty-three".