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132001454155 = 526400290831
BaseRepresentation
bin111101011101111100…
…1100101100001001011
3110121201102000122120111
41322323321211201023
54130314333013110
6140350213135151
712352055563444
oct1727371454113
9417642018514
10132001454155
1150a8841a27a
12216bb02a4b7
13c5a873aa2c
1465632222cb
153678911e8a
hex1ebbe6584b

132001454155 has 4 divisors (see below), whose sum is σ = 158401744992. Its totient is φ = 105601163320.

The previous prime is 132001454141. The next prime is 132001454159. The reversal of 132001454155 is 551454100231.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 551454100231 = 1980432784517.

It is not a de Polignac number, because 132001454155 - 233 = 123411519563 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (132001454159) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13200145411 + ... + 13200145420.

It is an arithmetic number, because the mean of its divisors is an integer number (39600436248).

Almost surely, 2132001454155 is an apocalyptic number.

132001454155 is a deficient number, since it is larger than the sum of its proper divisors (26400290837).

132001454155 is an equidigital number, since it uses as much as digits as its factorization.

132001454155 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26400290836.

The product of its (nonzero) digits is 12000, while the sum is 31.

Adding to 132001454155 its reverse (551454100231), we get a palindrome (683455554386).

The spelling of 132001454155 in words is "one hundred thirty-two billion, one million, four hundred fifty-four thousand, one hundred fifty-five".

Divisors: 1 5 26400290831 132001454155