1320032014113 has 4 divisors (see below), whose sum is σ = 1760042685488. Its totient is φ = 880021342740.

The previous prime is 1320032014069. The next prime is 1320032014139. The reversal of 1320032014113 is 3114102300231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1320032014113 - 2¹⁴ = 1320031997729 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1320032014113.

It is not an unprimeable number, because it can be changed into a prime (1320032014183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 220005335683 + ... + 220005335688.

It is an arithmetic number, because the mean of its divisors is an integer number (440010671372).

Almost surely, 2^{1320032014113} is an apocalyptic number.

It is an amenable number.

1320032014113 is a deficient number, since it is larger than the sum of its proper divisors (440010671375).

1320032014113 is an equidigital number, since it uses as much as digits as its factorization.

1320032014113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 440010671374.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 1320032014113 its reverse (3114102300231), we get a palindrome (4434134314344).

The spelling of 1320032014113 in words is "one trillion, three hundred twenty billion, thirty-two million, fourteen thousand, one hundred thirteen".