Base | Representation |
---|---|
bin | 1100000000010111000001… |
… | …1110010101111110110011 |
3 | 1201201221100002202021012011 |
4 | 3000011300132111332303 |
5 | 3212233224301100110 |
6 | 44024051033343351 |
7 | 2531456162314363 |
oct | 300056036257663 |
9 | 51657302667164 |
10 | 13200321503155 |
11 | 422a2523a1a86 |
12 | 1592388b67b57 |
13 | 749a28793a37 |
14 | 338c82ab69a3 |
15 | 17d585e6648a |
hex | c0170795fb3 |
13200321503155 has 4 divisors (see below), whose sum is σ = 15840385803792. Its totient is φ = 10560257202520.
The previous prime is 13200321503143. The next prime is 13200321503177. The reversal of 13200321503155 is 55130512300231.
13200321503155 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 13200321503155 - 217 = 13200321372083 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1320032150311 + ... + 1320032150320.
It is an arithmetic number, because the mean of its divisors is an integer number (3960096450948).
Almost surely, 213200321503155 is an apocalyptic number.
13200321503155 is a deficient number, since it is larger than the sum of its proper divisors (2640064300637).
13200321503155 is an equidigital number, since it uses as much as digits as its factorization.
13200321503155 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2640064300636.
The product of its (nonzero) digits is 13500, while the sum is 31.
Adding to 13200321503155 its reverse (55130512300231), we get a palindrome (68330833803386).
The spelling of 13200321503155 in words is "thirteen trillion, two hundred billion, three hundred twenty-one million, five hundred three thousand, one hundred fifty-five".
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