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132007069507 = 433069931849
BaseRepresentation
bin111101011110000111…
…1000000011101000011
3110121201210120221101111
41322330033000131003
54130322302211012
6140350533344151
712352154401645
oct1727417003503
9417653527344
10132007069507
1150a90605165
1221700a98057
13c5a9955921
146563c84895
153679170ba7
hex1ebc3c0743

132007069507 has 4 divisors (see below), whose sum is σ = 135077001400. Its totient is φ = 128937137616.

The previous prime is 132007069501. The next prime is 132007069517. The reversal of 132007069507 is 705960700231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 132007069507 - 23 = 132007069499 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 132007069507.

It is not an unprimeable number, because it can be changed into a prime (132007069501) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1534965882 + ... + 1534965967.

It is an arithmetic number, because the mean of its divisors is an integer number (33769250350).

Almost surely, 2132007069507 is an apocalyptic number.

132007069507 is a deficient number, since it is larger than the sum of its proper divisors (3069931893).

132007069507 is an equidigital number, since it uses as much as digits as its factorization.

132007069507 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3069931892.

The product of its (nonzero) digits is 79380, while the sum is 40.

Adding to 132007069507 its reverse (705960700231), we get a palindrome (837967769738).

The spelling of 132007069507 in words is "one hundred thirty-two billion, seven million, sixty-nine thousand, five hundred seven".

Divisors: 1 43 3069931849 132007069507