132010100113 has 4 divisors (see below), whose sum is σ = 132011759908. Its totient is φ = 132008440320.

The previous prime is 132010100111. The next prime is 132010100141. The reversal of 132010100113 is 311001010231.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 17314085889 + 114696014224 = 131583^2 + 338668^2 .

It is a cyclic number.

It is not a de Polignac number, because 132010100113 - 2¹ = 132010100111 is a prime.

It is a super-2 number, since 2×132010100113² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 132010100093 and 132010100102.

It is not an unprimeable number, because it can be changed into a prime (132010100111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 704256 + ... + 871777.

It is an arithmetic number, because the mean of its divisors is an integer number (33002939977).

Almost surely, 2^132010100113 is an apocalyptic number.

It is an amenable number.

132010100113 is a deficient number, since it is larger than the sum of its proper divisors (1659795).

132010100113 is an equidigital number, since it uses as much as digits as its factorization.

132010100113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1659794.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 132010100113 its reverse (311001010231), we get a palindrome (443011110344).

The spelling of 132010100113 in words is "one hundred thirty-two billion, ten million, one hundred thousand, one hundred thirteen".