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13201103035 = 52640220607
BaseRepresentation
bin11000100101101100…
…01101100010111011
31021002000012111222001
430102312031202323
5204013440244120
610021533241431
7645064344601
oct142266154273
937060174861
1013201103035
11566475110a
122685033277
131324c54093
148d3357871
15523e27e0a
hex312d8d8bb

13201103035 has 4 divisors (see below), whose sum is σ = 15841323648. Its totient is φ = 10560882424.

The previous prime is 13201103009. The next prime is 13201103039. The reversal of 13201103035 is 53030110231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13201103035 - 27 = 13201102907 is a prime.

It is a super-2 number, since 2×132011030352 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13201103039) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1320110299 + ... + 1320110308.

It is an arithmetic number, because the mean of its divisors is an integer number (3960330912).

Almost surely, 213201103035 is an apocalyptic number.

13201103035 is a deficient number, since it is larger than the sum of its proper divisors (2640220613).

13201103035 is an equidigital number, since it uses as much as digits as its factorization.

13201103035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2640220612.

The product of its (nonzero) digits is 270, while the sum is 19.

Adding to 13201103035 its reverse (53030110231), we get a palindrome (66231213266).

The spelling of 13201103035 in words is "thirteen billion, two hundred one million, one hundred three thousand, thirty-five".

Divisors: 1 5 2640220607 13201103035