Base | Representation |
---|---|
bin | 1100000000011010011010… |
… | …1101110010000111110011 |
3 | 1201202000200112002220221202 |
4 | 3000012212231302013303 |
5 | 3212242110232121433 |
6 | 44024321222241415 |
7 | 2531520552323414 |
oct | 300064655620763 |
9 | 51660615086852 |
10 | 13201231520243 |
11 | 422a67a046318 |
12 | 15925a188626b |
13 | 749b421869a0 |
14 | 338d2b8bd80b |
15 | 17d5dacc0ee8 |
hex | c01a6b721f3 |
13201231520243 has 16 divisors (see below), whose sum is σ = 14312894929536. Its totient is φ = 12103369799040.
The previous prime is 13201231520227. The next prime is 13201231520303. The reversal of 13201231520243 is 34202513210231.
It is not a de Polignac number, because 13201231520243 - 24 = 13201231520227 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13201231520843) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3918533 + ... + 6461993.
It is an arithmetic number, because the mean of its divisors is an integer number (894555933096).
Almost surely, 213201231520243 is an apocalyptic number.
13201231520243 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
13201231520243 is a deficient number, since it is larger than the sum of its proper divisors (1111663409293).
13201231520243 is a wasteful number, since it uses less digits than its factorization.
13201231520243 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2546174.
The product of its (nonzero) digits is 8640, while the sum is 29.
Adding to 13201231520243 its reverse (34202513210231), we get a palindrome (47403744730474).
The spelling of 13201231520243 in words is "thirteen trillion, two hundred one billion, two hundred thirty-one million, five hundred twenty thousand, two hundred forty-three".
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