Base | Representation |
---|---|
bin | 11000100101101101… |
… | …01111111110000001 |
3 | 1021002000110200101012 |
4 | 30102312233332001 |
5 | 204014004302113 |
6 | 10021540250305 |
7 | 645065502635 |
oct | 142266577601 |
9 | 37060420335 |
10 | 13201244033 |
11 | 566483803a |
12 | 26850a0995 |
13 | 1324ca3303 |
14 | 8d3392dc5 |
15 | 523e54aa8 |
hex | 312daff81 |
13201244033 has 4 divisors (see below), whose sum is σ = 13202345988. Its totient is φ = 13200142080.
The previous prime is 13201244009. The next prime is 13201244053. The reversal of 13201244033 is 33044210231.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 3575083264 + 9626160769 = 59792^2 + 98113^2 .
It is a cyclic number.
It is not a de Polignac number, because 13201244033 - 26 = 13201243969 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13201244053) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 532808 + ... + 557033.
It is an arithmetic number, because the mean of its divisors is an integer number (3300586497).
Almost surely, 213201244033 is an apocalyptic number.
It is an amenable number.
13201244033 is a deficient number, since it is larger than the sum of its proper divisors (1101955).
13201244033 is a wasteful number, since it uses less digits than its factorization.
13201244033 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1101954.
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 13201244033 its reverse (33044210231), we get a palindrome (46245454264).
The spelling of 13201244033 in words is "thirteen billion, two hundred one million, two hundred forty-four thousand, thirty-three".
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