13201300000113 has 8 divisors (see below), whose sum is σ = 17602314964800. Its totient is φ = 8800575851088.

The previous prime is 13201300000099. The next prime is 13201300000123. The reversal of 13201300000113 is 31100000310231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13201300000113 - 2⁸ = 13201299999857 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13201300000092 and 13201300000101.

It is not an unprimeable number, because it can be changed into a prime (13201300000123) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 72597973 + ... + 72779586.

It is an arithmetic number, because the mean of its divisors is an integer number (2200289370600).

Almost surely, 2^{13201300000113} is an apocalyptic number.

It is an amenable number.

13201300000113 is a deficient number, since it is larger than the sum of its proper divisors (4401014964687).

13201300000113 is a wasteful number, since it uses less digits than its factorization.

13201300000113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 145407831.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 13201300000113 its reverse (31100000310231), we get a palindrome (44301300310344).

The spelling of 13201300000113 in words is "thirteen trillion, two hundred one billion, three hundred million, one hundred thirteen", and thus it is an aban number.